3 ms·
That's still only relative to an oracle, though (i.e., BQP^O vs NP^O). We also have oracle separations of P and NP, and that proves nothing about P vs NP withou
by moefh 8y ago
That's still only relative to an oracle, though (i.e., BQP^O vs NP^O). We also have oracle separations of P and NP, and that proves nothing about P vs NP without an oracle.