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My solution never mentioned Bayes! So, don't have to "be a Bayesian" to use what I wrote. I just used conditional expectation which, of course, with full deta
by graycat 8y ago
My solution never mentioned Bayes! So, don't have to "be a Bayesian" to use what I wrote.
I just used conditional expectation which, of course, with full details, is from the Radon-Nikodym theorem in measure theory as in, say, Rudin, Real and Complex Analysis with a nice, novel proof from von Neumann.
- davidsrosenberg 8y agoYes, of course. A “Bayes prediction function” has nothing to do with Bayesian. Bayes had a lot of things named after him ;)