4 ms·
While not covered in the article, it's likely that the same process works with more than two participants, as long as one makes the partitioning and some other
by paulclinger 8y ago
While not covered in the article, it's likely that the same process works with more than two participants, as long as one makes the partitioning and some other one (adversary) freezes one district; so A partitions, B freezes one and partitions again, C freezes one and partitions again, A freezes one and partitions and so on while there are districts.