3 ms·
You're right. There's no undefined behaviour for ==: Two pointers compare equal if and only if both are null pointers, both are pointers to the same object (in
by tzahola 8y ago
You're right. There's no undefined behaviour for ==:
Two pointers compare equal if and only if both are null pointers, both are pointers to the same object (including a pointer to an object and a subobject at its beginning) or function, both are pointers to one past the last element of the same array object, or one is a pointer to one past the end of one array object and the other is a pointer to the start of a different array object that happens to immediately follow the first array object in the address space.