4 ms·

From reading the spec it seems that is undefined behaviour for anything other than `&b + 1`. That is one past the end of b is fine but not `&b + 2` etc.

• zubyak 8y ago
  I wonder why someone decided that accessing "one past the end" should be fine
  • jwilk 8y ago
    It's explained in the addendum to the article.
    • zubyak 8y ago
      thanks
  • mcguire 8y ago
    Short answer: so you can walk a pointer down the elements of an array without having to have weird code to deal with the end.
  • deleted 8y ago
    [deleted]