4 ms·
This has nothing to do with causation. The solution to the first problem is this simple: if((a > 1 & b > 1 & c > 1) | (a < 1 & b < 1 & c < 1)){ eve
by nonbel 8y ago
This has nothing to do with causation. The solution to the first problem is this simple:
if((a > 1 & b > 1 & c > 1) |
(a < 1 & b < 1 & c < 1)){
event
}else{
no_event
}
They introduce a bunch of artificial constraints and then get into weirdness about "cubies" and 3-D sandwiches which is fine for a puzzles sake but what does this have to do with "the math of causation"?
- deleted 8y ago[deleted]
- TheOtherHobbes 8y agoYour solution does not solve the problem posed. I suggest you read the article again - mors than once.
- nonbel 8y agoIf by problem posed you mean the one with artifical constraints then sure. Once again, what does that have to do with "math of causation though".