It seems to me like the n-th number repeats 2^n times, with 1 being in the middle of each sequence. From this, you could get the 13th number quite easily. Inter

It seems to me like the n-th number repeats 2^n times, with 1 being in the middle of each sequence. From this, you could get the 13th number quite easily. Interpreting it would be a lot more difficult though. Interestingly, normal binary has the same pattern, but with different offsets for the start of the sequence.