3 ms·
Actually, it puts the responsibility higher in the stack. The first error effectively terminates the computation, so subcomputations can ignore them and the cal
by solidsnack9000 8y ago
Actually, it puts the responsibility higher in the stack. The first error effectively terminates the computation, so subcomputations can ignore them and the caller can decide what to do with them.
One good thing about this is not having to push down anything to do with logging or reporting into subcomputations.