4 ms·

Since I don't have py3 installed at the moment, I can't check anything, but I'd guess this is two closures with distinct ids but the same environments, and == i

• UncleEntity 8y ago
  >>> fs[0].__closure__, fs[1].__closure__ ((<cell at 0x7f4e9111b048: int object at 0x7f4e98e99500>,), (<cell at 0x7f4e9111b048: int object at 0x7f4e98e99500>,)) So lambda isn't broken it's the list comprehension going all wonky with its local variables methinks.
  • abecedarius 8y ago
    All right, I looked into this using repl.it. The __closure__ field is not actually a closure in the usual sense of the word -- it's the environment of the closure, and fs[0] and fs[1] are expected to share the same environment. If you look at the identities of fs[0] and fs[1] themselves, they are different. It's as I said originally, just with a confusing name for the environment field.