Thanks for the chuckle. To save everyone from having to look this up on Stack Overflow: .map passes two arguments to the function it calls - the value and the

Thanks for the chuckle. To save everyone from having to look this up on Stack Overflow: .map passes two arguments to the function it calls - the value and the index. The parseInt function takes up to two arguments, a string and a radix. So there’s nothing broken here about .map, you just aren’t expecting the second optional argument for parseInt. So the actual equivalents are: ['1','1','1'].map(parseInt) And ['1','1','1'].map((n, index) => parseInt(n, index))