4 ms·
So just a quick calculation: Assuming that the rocket has moment of inertia similar to a hollow cylinder with radius 1ft, conversion from rotation energy to li
by kuprel 8y ago
So just a quick calculation:
Assuming that the rocket has moment of inertia similar to a hollow cylinder with radius 1ft, conversion from rotation energy to linear is perfect, and final linear velocity is 5000 mph, the rocket would have to be spinning at
1/2 * I * w^2 = 1/2 * m * v^2
1/2 * (m * r^2) * w^2 = 1/2 * m * v^2
w = v / r = 7333 rad/s ~ 70,000 rpm
Maybe the payload of the rocket could be connected to the body of the rocket with magnetic bearings so that it isn't spinning, i.e. not experiencing the massive accelerations.