5 ms·

Does that prevent the usage shown in the blog post? std::optional<unsigned> opt = firstEvenNumberIn(text); if (opt)

• geezerjay 8y ago
  That usage means "was the optional value set?" That's the whole point of an optional type, and there is absolutely no reason to prevent it.
  • hoppelhase 8y ago
    There is. See: https://news.ycombinator.com/item?id=17275784 https://news.ycombinator.com/item?id=17275784
    • geezerjay 8y ago
      I've already explained why that argument makes no sense https://news.ycombinator.com/item?id=17276845 https://news.ycombinator.com/item?id=17276845
      • hoppelhase 8y ago
        Could you elaborate more on why having the compiler tell us that we forgot to change something wouldn't be a good thing?