3 ms·
Then the supply before the diode supplies 3.3V + the voltage drop; for example 3.6V.
by Faaak 8y ago
Then the supply before the diode supplies 3.3V + the voltage drop; for example 3.6V.
- gizmo686 8y agoSo now you need a 3.6V power regulator, in additition to the 3.3V one you likely already have for all the components built for 3.3V.
- 0110011 8y agoOr another diode to put in-line with the DP circuitry. It's probably not ideal from a low-power perspective but if that's what you gotta do to make robust and compliant hardware, you do it.
- Faaak 8y agoA Schottky will drop .3V; That's within the range (±10%) specified in the specs
- kevincox 8y agoYes. But now you have given up all of your tolerance so you better have a perfect (or over-voltage) power supply. This means that you now have less choice in power supply.
- Faaak 8y agoAs a parent commenter said, you could also put a diode for your circuitry. You would then have a single 3.7V supply.
- snovv_crash 8y agoAnd 10% higher power draw just for this one feature. No, there are better ways to solve this.
- deleted 8y ago[deleted]