2 ms·
It depends - the "v^2" term quickly passes the linear "m" term for some scenarios. If I've got a choice between making it ten times as heavy or capable of spinn
by bigiain 9y ago
It depends - the "v^2" term quickly passes the linear "m" term for some scenarios. If I've got a choice between making it ten times as heavy or capable of spinning 10 times as fast, I don't want more mass there.