From the other story about the key leak, it seems the key-generation is based on traversing a 40x40 matrix of 56-bit numbers. If my maths is right, that adds u

From the other story about the key leak, it seems the key-generation is based on traversing a 40x40 matrix of 56-bit numbers. If my maths is right, that adds up to (40x40x56)/8 = 11,200 bytes. Which really should be peanuts for any (half-way modern) FPGA architecture, storage-wise.