Hmmm... If Ininterpret their proof (i.e. “Puzzle 2”) correctly, they prove that there’s no deterministic solution that yields probability > 50% for any two numb

Hmmm... If Ininterpret their proof (i.e. “Puzzle 2”) correctly, they prove that there’s no deterministic solution that yields probability > 50% for any two numbers... the idea of the solution I posted (which is deterministic) is that you have >= 50% for all numbers, and > 50% for some numbers.