3 ms·
IME it's easy to get an error in bigint libraries if you do something like 2 ** (2 ** n) for some n greater than a few dozen. Because then you will have
by TazeTSchnitzel 9y ago
IME it's easy to get an error in bigint libraries if you do something like
2 ** (2 ** n)
for some n greater than a few dozen. Because then you will have
2**n
digits, and the internal value holding the number of digits is limited to
2**32
or
2**64