3 ms·
Consumption: 7M Gallons/day = 26.5E3 m^3 / day (fed to foxconn's personal black hole) Area of Lake Michigan: 58000 km^2 = 58E9 m^2 Corresponds to 4.6E-7 m/day
by CodesInChaos 9y ago
Consumption: 7M Gallons/day = 26.5E3 m^3 / day (fed to foxconn's personal black hole)
Area of Lake Michigan: 58000 km^2 = 58E9 m^2
Corresponds to 4.6E-7 m/day or about 6 years for one millimeter or about 150 years for the oddly specific 25.4mm you were asking for.
If we take the 39% loss figure from the article, we get 15 years/1mm and 390 years/25.4mm.
- rascul 9y agoThanks.
- PeterStuer 9y agoSo does that mean it takes just 390 Foxconns to have the lake drop an inch each year?