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.split_at_mut(), there you go. But I understand that there are cases when Rust rejects correct program, that is where we need unsafe to build safe abstraction.

.split_at_mut(), there you go. But I understand that there are cases when Rust rejects correct program, that is where we need unsafe to build safe abstraction. Come back to additional mental cost, it’s just the same debate between static & dynamic typed language. Either you write more, specify constraints, and have the usage checked or you write less, imply your constraints and must satisfy the constraints of usage by yourself (or with helper tools/tests). To me that’s just “when” I have to spend the mental resource, and the total cost is roughly the same. But then, knowing the separation helps to choose which tool for which type of project.

sirclueless 8y ago
I don't think this is just about being more or less verbose. It's about the awkward ways it contorts the ways you write programs. For example, in C++ you might write an asynchronous job scheduler with an API like the following: void Scheduler::schedule(const Job& job, Result* result); void Scheduler::wait(); The consumer of this API in C++ has an easy job. They can create an array of results and iteratively call schedule(jobs[i], &results[i]) for each job, and then call wait(). A similar API in Rust would be a giant pain in the neck to use, because there's no simple way to collect the results. You'd likely want to scrap this API entirely and have Scheduler expose some kind of queue or something. My point is that these extra constraints are not just extra typing locally to specify how you're using lifetimes. You'll likely have to rethink the way you write APIs and whole programs in Rust because of the ways it restricts mutability. Which is OK, it's a trade-off, all I'm saying is the safety doesn't come for free.
- GolDDranks 8y ago
  While there might be all kinds of troubles _implementing_ that API, I don't think it wouldn't be that hard to use. You would need to have a valid "not ready" state for the results, because Rust requires that they are in some state at the moment they are constructed. From the lifetime perspective, the data structure where the results live should outlive the schedule calls – but that isn't a problem if you construct the array first. There will be a lifetime requirement but that's it. The mutability thing isn't a problem. You can allocate a vector of results and jobs, and then have a mutable iterator over them, zip them together and then iterate over that. There's no problem passing mutable references to each of the elements.
  - sirclueless 8y ago
    The problem is that schedule() needs to mutate result asynchronously at some point in the future. It can't do this if result is a mutable reference, since it needs to return immediately so borrowing a reference doesn't work. It also can't take ownership of result, since it has no way to give it back (short of changing the API, for example by making wait() return a collection of results). The right way to implement the API above is for schedule() to take Arc<Mutex<Result>>, and explicitly share mutable ownership over each individual result between some unspecified asynchronous execution mechanism and the caller of schedule(). This makes the calling code significantly more complicated as it needs to incur the overhead of atomic reference counting and a mutex per result, and must try to lock each result before using it, even if it knows there are no other owners of the result due to wait() returning.
    - GolDDranks 8y ago
      I don't see the problem with returning immediately after borrowing a reference, if the scheduler lives shorter than the results (if it doesn't, holding the reference would be unsound): https://play.rust-lang.org/?gist=226f92bc311dbac05c112b10ba434db6&version=stable&mode=debug https://play.rust-lang.org/?gist=226f92bc311dbac05c112b10ba4...
      - sirclueless 8y ago
        You're exclusively borrowing res_a, res_b and res_c for the lifetime of the scheduler. Which works fine since res_a, res_b and res_c are hard-coded variables with separate lifetimes. What rust doesn't know how to do is borrow mutable references to elements of a container without borrowing the entire container. https://play.rust-lang.org/?gist=1324a919ca5d0e2f16e445364a790d5a&version=undefined&mode=undefined https://play.rust-lang.org/?gist=1324a919ca5d0e2f16e445364a7...
        unrealhoang 8y ago
        The sibling comment shows how to do that in safe Rust code. But then, even when you have much more complex control that Rust compiler can not prove safety, you can still resort to unsafe, build your algo, and wrap it into a safe API, just like `split_at_mut`

sirclueless 8y ago

I don't think this is just about being more or less verbose. It's about the awkward ways it contorts the ways you write programs. For example, in C++ you might write an asynchronous job scheduler with an API like the following: void Scheduler::schedule(const Job& job, Result* result); void Scheduler::wait(); The consumer of this API in C++ has an easy job. They can create an array of results and iteratively call schedule(jobs[i], &results[i]) for each job, and then call wait(). A similar API in Rust would be a giant pain in the neck to use, because there's no simple way to collect the results. You'd likely want to scrap this API entirely and have Scheduler expose some kind of queue or something. My point is that these extra constraints are not just extra typing locally to specify how you're using lifetimes. You'll likely have to rethink the way you write APIs and whole programs in Rust because of the ways it restricts mutability. Which is OK, it's a trade-off, all I'm saying is the safety doesn't come for free.

GolDDranks 8y ago
While there might be all kinds of troubles _implementing_ that API, I don't think it wouldn't be that hard to use. You would need to have a valid "not ready" state for the results, because Rust requires that they are in some state at the moment they are constructed. From the lifetime perspective, the data structure where the results live should outlive the schedule calls – but that isn't a problem if you construct the array first. There will be a lifetime requirement but that's it. The mutability thing isn't a problem. You can allocate a vector of results and jobs, and then have a mutable iterator over them, zip them together and then iterate over that. There's no problem passing mutable references to each of the elements.
- sirclueless 8y ago
  The problem is that schedule() needs to mutate result asynchronously at some point in the future. It can't do this if result is a mutable reference, since it needs to return immediately so borrowing a reference doesn't work. It also can't take ownership of result, since it has no way to give it back (short of changing the API, for example by making wait() return a collection of results). The right way to implement the API above is for schedule() to take Arc<Mutex<Result>>, and explicitly share mutable ownership over each individual result between some unspecified asynchronous execution mechanism and the caller of schedule(). This makes the calling code significantly more complicated as it needs to incur the overhead of atomic reference counting and a mutex per result, and must try to lock each result before using it, even if it knows there are no other owners of the result due to wait() returning.
  - GolDDranks 8y ago
    I don't see the problem with returning immediately after borrowing a reference, if the scheduler lives shorter than the results (if it doesn't, holding the reference would be unsound): https://play.rust-lang.org/?gist=226f92bc311dbac05c112b10ba434db6&version=stable&mode=debug https://play.rust-lang.org/?gist=226f92bc311dbac05c112b10ba4...
    - sirclueless 8y ago
      You're exclusively borrowing res_a, res_b and res_c for the lifetime of the scheduler. Which works fine since res_a, res_b and res_c are hard-coded variables with separate lifetimes. What rust doesn't know how to do is borrow mutable references to elements of a container without borrowing the entire container. https://play.rust-lang.org/?gist=1324a919ca5d0e2f16e445364a790d5a&version=undefined&mode=undefined https://play.rust-lang.org/?gist=1324a919ca5d0e2f16e445364a7...
      - unrealhoang 8y ago
        The sibling comment shows how to do that in safe Rust code. But then, even when you have much more complex control that Rust compiler can not prove safety, you can still resort to unsafe, build your algo, and wrap it into a safe API, just like `split_at_mut`