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No. If pi would contain itself it would be a rational number. We have a proof that pi is irrational, hence it cannot contain itself.
by avian 9y ago
No. If pi would contain itself it would be a rational number. We have a proof that pi is irrational, hence it cannot contain itself.
- gowld 9y agoSpecifically, if pi contains itself, that means "pi - pi/b^k" is a terminating fraction N in base b", where b is your choice of base (like base 10), and k is some positive integer. So pi = N/(1-b^k) which is rational. (And if you set k=0, you get that pi "contains itself" in the sense that pi from the 1st digit onward is of course pi)