2 ms·
I agree with you. But this quote is badly written by the author -- they should have clarified further. In fact, compilers don't remove check of divisors that p
by ychen306 8y ago
I agree with you. But this quote is badly written by the author -- they should have clarified further. In fact, compilers don't remove check of divisors that prevents div-by-0 precisely for this reason. What the authors mean is someting like this:
>if (!msize) msize = 1 / msize; // provoke a signal