3 ms·

I guess the numbers should be primes... 4+1=3+2

• shagie 9y ago
  10 = 5 + 5 = 7 + 3
  • eecc 9y ago
    that's right... even prime isn't enough
    • shagie 9y ago
      Prime is ok if it’s multiplied (there is one and only one prime factorization of a number).... but that can get to absurdly large numbers. Still, consider the word ‘abe’ with a = 2, b = 3, c = 5, d = 7 and e = 11. abe would then be 2^1 * 3^1 * 5^0 * 7^0 * 11^1. ‘abba’ would be 2^2 * 3^2. Each anagram would have a distinct value. See also Gödel numbering and FRACTRAN.
      • eecc 9y ago
        That’s right... stupid me, it’s the base of public key cryptography (doh)