4 ms·
Reference values are part of the Java language. It's the reason "==" doesn't do what you'd expect it to, and why "a = ..." inside a method (assuming "a" was a p
by jjnoakes 9y ago
Reference values are part of the Java language. It's the reason "==" doesn't do what you'd expect it to, and why "a = ..." inside a method (assuming "a" was a parameter) doesn't affect the caller.