2 ms·
>Later you have x=2i or x=-2i. To be clear, by the time I got to this statement, I had changed the question (from a base of Q to C) Further, the complete stat
by gizmo686 9y ago
>Later you have x=2i or x=-2i.
To be clear, by the time I got to this statement, I had changed the question (from a base of Q to C)
Further, the complete statement I was making at that point was:
If ((x^3+4x=0) AND x != 0) then ((x=2i) OR (x=-2i))
I am not allowing x to vary at all here. Suppose, for the sake of arguement, we had x=2i. It would still be true that ((x=2i) OR (x=-2i)).
> Persisting with the idea that you can view x as an element in the base ring and at the same time allowing its value to change or vary indicates you don’t really understand these issues.
Persisting with the idea that I am doing this indicates that your are not reading what I am writing.