"booting both under the same revision of the same OS" It should be irrelevant in Apple's case anyway since they run their own OS. If their OS is faster for a c

"booting both under the same revision of the same OS" It should be irrelevant in Apple's case anyway since they run their own OS. If their OS is faster for a certain task than some other OS then that's part of what you would define as "faster" for a user of the device. Right? Am I missing something?