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Is P(a|b) = ( P(b) * P(b|a) ) / P(b) more true when the probabilities are from a binomial distribution as opposed to poisson, or am I just confused and it doesn
by 0xdeadbeefbabe 9y ago
Is P(a|b) = ( P(b) * P(b|a) ) / P(b) more true when the probabilities are from a binomial distribution as opposed to poisson, or am I just confused and it doesn't matter.