4 ms·
Yes, this puzzles me too. Maybe the fact that you can redefine both the methods of `foo` and the function `Foo` at any time? And you can also change `foo.protot
by lou1306 9y ago
Yes, this puzzles me too. Maybe the fact that you can redefine both the methods of `foo` and the function `Foo` at any time? And you can also change `foo.prototype`, I guess?