3 ms·
Approximating the station as a hollow shell of constant thickness, the mass would scale with the surface area. The volume would scale proportional to the surfac
by hughes 9y ago
Approximating the station as a hollow shell of constant thickness, the mass would scale with the surface area. The volume would scale proportional to the surface area to the power of 3/2.
So 6.6x the mass gets you 6.6x the surface area, which gets you about 17x the volume, or ~5600m^3
- sq_ 9y agoAh, figured I was forgetting something. Editing my comment to reflect what you said. Thanks for the correction!