4 ms·

thank you so much for your response,actually rearragning the terms to find 'b' gives me 3logb = 2loga - 5 {upon subtracting 5 from both the sides}. this is wher

by pencil 16y ago

thank you so much for your response,actually rearragning the terms to find 'b' gives me 3logb = 2loga - 5 {upon subtracting 5 from both the sides}. this is where i need help.please look into my partial fractions problems as well if you got the time.

RiderOfGiraffes 16y ago
But you still don't have b as the subject of the equation. You need to get to "b=..." If you don't know how to do that, then at least tell us what you've tried. Can you make x the subject of this equation: log(x)+3=2t ? In other words, if the equation log(x)+3=2t is always satisfied, what does x equal? And I will look at the partial fractions, but I'd like to concentrate on this first. Actually, what is your definition of a logarithm? The last time we had a conversation I asked you some questions to assess your level of knowledge and you never answered them: http://news.ycombinator.com/item?id=1107996 http://news.ycombinator.com/item?id=1107996 It seems to me looking over other times you've asked questions that you claim you want to get into math, and you probably think you're doing lots of stuff, but in reality I've seen no evidence of you actually trying things. Gaining skills is a matter of spending the time. In math in particular, if you haven't spent ages getting loads of wrong answers then you won't have any real intuition as to what to do. You need loads of wrong answers, from which you can start to identify "good wrong answers". From those good wrong answers you can build an intuition as to what might work, and you can start to find excellent wrong answers. Then the moment comes when you see how to convert an excellent wrong answer into a right answer. With practice this becomes second nature, and after a time you wonder why you ever found it difficult. But until you've put in the hours of practice, it doesn't happen. People think doing math is a matter of somehow finding the right process and then following it. "Tell me what to do" is the perpetual cry. You need to try stuff. Try re-arranging the equations repeatedly into different forms until, maybe, one looks familiar. Don't just stare at stuff hoping inspiration will strike, and don't think there's a magic formula for finding the right next step. That's not how it works. So tell me, how many different ways can you rearrange the equation: log(x)+3=2t ?
- pencil 16y ago
  i completely agree with you sir and i really appologise for not responding to this thread http://news.ycombinator.com/item?id=1107996 http://news.ycombinator.com/item?id=1107996 to be honest with you i really don't know where i stand .what's my level of competence. i recently gained interest in math and physics because i regret not taking these two subjects seriously back in college.now i work for a bank which pay's peanuts.i don't intend to get a job which helps me build my math/physics skills,i just wanna learn it because i have a burning desire to learn it.it's as simple as that. yes.math requires hours and days of practice which i'am religiously doing but it's not enough for me as it's very evident by the level of knowledge/intellect that i possess. with that being said the number of ways arranging the equation log(x)+3=2t hmm.. log(x)=2t-3 am i right??hope i'am not bullshitting you. by the way the only definition of logarithm that i know is 'log is inverse of exponents'
  - RiderOfGiraffes 16y ago
    So what does that mean? OK, here are some terms to simplify. In each case, what is a simpler way to write the expression: x^3 * x^5 (t^3)^2 u^(3^2) Expand the following: (g+2)^2 (z-3)^3 Now, if x=10^y, what does y equal?
    - pencil 16y ago
      x^3+5=x^8 t^3 * t^3 = t^6 i guess it's u^6 g^2+4g+4 not sure abt (z-3)^3 expanding (z-3)^3 could it be: (z-3).(z+3)^2 ?? =>(z-3) (z^2+3z+9)
      - RiderOfGiraffes 16y ago
        OK, in the first one you need brackets : x^3+5 is not usually understood to be the same as x^(3+5), but the answer is right, and the process is right. The others are right too. So (g+2)^2 is equal to g^2+4g+4, but it's also equal to (g+2).(g+2) [where I've used the dot for multiplication] Does that help you for (z-3)^3 ??
    - 16y ago
deleted 16y ago
[deleted]
RiderOfGiraffes 16y ago
Let's go much simpler, right back to logs basics. If y=log(x) (with 10 as the base of the logarithms) then what does x equal in terms of y?
- pencil 16y ago
  i'am assuming this would end up in some number called 'e' which i came accross somewhere in the past.please help..i'am not sure what that number means and how to get it
  - RiderOfGiraffes 16y ago
    No, it doesn't. I've given you the rules, and I've pointed you at two web pages that explain the rules and work through some examples. You seem to keep wanting me to just give you the answers without showing me any working for yourself. This is not the medium for teaching you about the basic, basic, basic rules of elementary algebra. There are loads of tutorials on the web - try using Google to search for tutorials on logarithms. When you tell me what you've searched for, and what the first rules are that they give you, then I'll start helping again.
RiderOfGiraffes 16y ago
I found you a tutorial: http://www.phon.ucl.ac.uk/cgi-bin/wtutor?tutorial=t-log http://www.phon.ucl.ac.uk/cgi-bin/wtutor?tutorial=t-log Work through that - it will help with your basic understanding of what's going on.
- pencil 16y ago
  one of the best tutorials on logs i've ever come accross.thanks a million!!!! please look into my partial fraction problems when you get the time.so far i've been able to solve a couple of them but the above mentioned one is bothering me a lot.
  - RiderOfGiraffes 16y ago
    It was the very, very first one I found with a Google search for "logarithm tutorial". Have you not tried searching for tutorials?

by pencil 16y ago

RiderOfGiraffes 16y ago

But you still don't have b as the subject of the equation. You need to get to "b=..." If you don't know how to do that, then at least tell us what you've tried. Can you make x the subject of this equation: log(x)+3=2t ? In other words, if the equation log(x)+3=2t is always satisfied, what does x equal? And I will look at the partial fractions, but I'd like to concentrate on this first. Actually, what is your definition of a logarithm? The last time we had a conversation I asked you some questions to assess your level of knowledge and you never answered them: http://news.ycombinator.com/item?id=1107996 http://news.ycombinator.com/item?id=1107996 It seems to me looking over other times you've asked questions that you claim you want to get into math, and you probably think you're doing lots of stuff, but in reality I've seen no evidence of you actually trying things. Gaining skills is a matter of spending the time. In math in particular, if you haven't spent ages getting loads of wrong answers then you won't have any real intuition as to what to do. You need loads of wrong answers, from which you can start to identify "good wrong answers". From those good wrong answers you can build an intuition as to what might work, and you can start to find excellent wrong answers. Then the moment comes when you see how to convert an excellent wrong answer into a right answer. With practice this becomes second nature, and after a time you wonder why you ever found it difficult. But until you've put in the hours of practice, it doesn't happen. People think doing math is a matter of somehow finding the right process and then following it. "Tell me what to do" is the perpetual cry. You need to try stuff. Try re-arranging the equations repeatedly into different forms until, maybe, one looks familiar. Don't just stare at stuff hoping inspiration will strike, and don't think there's a magic formula for finding the right next step. That's not how it works. So tell me, how many different ways can you rearrange the equation: log(x)+3=2t ?

pencil 16y ago
i completely agree with you sir and i really appologise for not responding to this thread http://news.ycombinator.com/item?id=1107996 http://news.ycombinator.com/item?id=1107996 to be honest with you i really don't know where i stand .what's my level of competence. i recently gained interest in math and physics because i regret not taking these two subjects seriously back in college.now i work for a bank which pay's peanuts.i don't intend to get a job which helps me build my math/physics skills,i just wanna learn it because i have a burning desire to learn it.it's as simple as that. yes.math requires hours and days of practice which i'am religiously doing but it's not enough for me as it's very evident by the level of knowledge/intellect that i possess. with that being said the number of ways arranging the equation log(x)+3=2t hmm.. log(x)=2t-3 am i right??hope i'am not bullshitting you. by the way the only definition of logarithm that i know is 'log is inverse of exponents'
- RiderOfGiraffes 16y ago
  So what does that mean? OK, here are some terms to simplify. In each case, what is a simpler way to write the expression: x^3 * x^5 (t^3)^2 u^(3^2) Expand the following: (g+2)^2 (z-3)^3 Now, if x=10^y, what does y equal?
  - pencil 16y ago
    x^3+5=x^8 t^3 * t^3 = t^6 i guess it's u^6 g^2+4g+4 not sure abt (z-3)^3 expanding (z-3)^3 could it be: (z-3).(z+3)^2 ?? =>(z-3) (z^2+3z+9)
    - RiderOfGiraffes 16y ago
      OK, in the first one you need brackets : x^3+5 is not usually understood to be the same as x^(3+5), but the answer is right, and the process is right. The others are right too. So (g+2)^2 is equal to g^2+4g+4, but it's also equal to (g+2).(g+2) [where I've used the dot for multiplication] Does that help you for (z-3)^3 ??
  - 16y ago

deleted 16y ago

[deleted]

RiderOfGiraffes 16y ago

Let's go much simpler, right back to logs basics. If y=log(x) (with 10 as the base of the logarithms) then what does x equal in terms of y?

pencil 16y ago
i'am assuming this would end up in some number called 'e' which i came accross somewhere in the past.please help..i'am not sure what that number means and how to get it
- RiderOfGiraffes 16y ago
  No, it doesn't. I've given you the rules, and I've pointed you at two web pages that explain the rules and work through some examples. You seem to keep wanting me to just give you the answers without showing me any working for yourself. This is not the medium for teaching you about the basic, basic, basic rules of elementary algebra. There are loads of tutorials on the web - try using Google to search for tutorials on logarithms. When you tell me what you've searched for, and what the first rules are that they give you, then I'll start helping again.

RiderOfGiraffes 16y ago

I found you a tutorial: http://www.phon.ucl.ac.uk/cgi-bin/wtutor?tutorial=t-log http://www.phon.ucl.ac.uk/cgi-bin/wtutor?tutorial=t-log Work through that - it will help with your basic understanding of what's going on.

pencil 16y ago
one of the best tutorials on logs i've ever come accross.thanks a million!!!! please look into my partial fraction problems when you get the time.so far i've been able to solve a couple of them but the above mentioned one is bothering me a lot.
- RiderOfGiraffes 16y ago
  It was the very, very first one I found with a Google search for "logarithm tutorial". Have you not tried searching for tutorials?