3 ms·
heh, come to think of it, so is the first one: it is given that log((a-b)/4) = log sqrta + log sqrtb, thus (a-b)/4 = sqrt(ab), thus, ((a-b)/4)^2 = ab, thus, (a
by ghoul2 16y ago
heh, come to think of it, so is the first one:
it is given that log((a-b)/4) = log sqrta + log sqrtb, thus
(a-b)/4 = sqrt(ab),
thus, ((a-b)/4)^2 = ab,
thus, (a-b)^2 = 16ab,
thus a^2 - 2ab + b^2 = 16ab. Adding 4ab to both sides,
a^2 + 2ab + b^2 = 20 ab, giving
(a+b)^2 = 20ab.
- pencil 16y agoThank you so much.what about the rest??any idea??
- ghoul2 16y agothe others are even easier than these. I think if you are really trying to get back into math you should not lose patience so easily and spend a bit more time trying, and don't ask for help even if it takes many days to get these questions - otherwise it will never click for you again (my own personal experience). I also hope I have not given you full solutions to homework problems you were supposed to solve by yourself. The wikipedia page on partial fractions gives you good directions on how to solve it.