4 ms·

VarArgs usage would be even better: employees.filter(predicate1, predicate2, predicate3);

• ekiru 16y ago
  Perl 6 would do that like this: @employees.grep($predicate1 & $predicate2 & $predicate3); The predicates can be a function, a regex, a type, or anything that can be smart-matched against. Alternately, if you want to get the employees that match any of the predicates, you'd do the following: @employees.grep($predicate1 | $predicate2 | $predicate3); Or, if you want the employees that match only one of the predicates (think of xor): @employees.grep($predicate1 ^ $predicate2 ^ $predicate3); These can also be written, respectively, as: @employees.grep(all($predicate1, $predicate2, $predicate3)); @employees.grep(any($predicate1, $predicate2, $predicate3)); @employees.grep(one($predicate1, $predicate2, $predicate3)); And, if you want things that match none of the predicates: @employees.grep(none($predicate1, $predicate2, $predicate3)); You can combine these junction constructors. For example: @employees.grep(all($predicate1, $predicate2) ^ $predicate3);