3 ms·
If by "just work" you mean testing each constituent vertex, it'll fail. Consider the case when the needle is at the midpoint of a line between two points far aw
by snaily 9y ago
If by "just work" you mean testing each constituent vertex, it'll fail. Consider the case when the needle is at the midpoint of a line between two points far away.
- geophile 9y agoNo, that's not what I mean. A point is represented by a z-value at the resolution of space. A non-point is approximated by multiple z-values, at varying resolutions. You can trade the accuracy of the approximation against the number of z-values. I explained the NN algorithm in another comment on this thread. It shouldn't matter if some of the adjacent z-values are actually from the approximation of the same object.