3 ms·
Uhm... no, I think not: to get information out of the quantum computer as output for the ”previous user” it needs to go through an explicit phase of observation
by qubex 9y ago
Uhm... no, I think not: to get information out of the quantum computer as output for the ”previous user” it needs to go through an explicit phase of observation, busting all the state (?), and loading up new data for the subsequent user’s computation also constitutes ’observation’ since there’s knowledge of the inner state of the quantum system outside the strict confines of the quantum system. I really don’t think you could at any moment in time get information out of a side-channel, otherwise the thing wouldn’t compute.
(Yup, of course they’re extremely simplistic in terms of inner architecture, but that’s quite beside the point, as I think we both agree.)
- tlb 9y agoIt's true that the quantum state can only be observed once, but at the end of the observation the resolved state exists classically in the phase of the resonating elements. Also, the input vector continues to be there. Leaking either is a leak.