3 ms·
Well, they start with an assumption that the halting problem is addressed simply by "running out of gas." I could easily see a dev assessing the infinite loop p
by jancsika 9y ago
Well, they start with an assumption that the halting problem is addressed simply by "running out of gas." I could easily see a dev assessing the infinite loop potential and glibly thinking, "well, that would just run out of gas, too."
That doesn't explain the lack of guarantee on "constant". What is the technical detail which prevents such a guarantee?
- falsprofet 9y agoI don't know, but constant as a function return value signature does not make much sense at all.