3 ms·

This requires that some-command takes input from stdin (many commands don't) and that there's only a single input. What about: process-stuff --file <(make-in

This requires that some-command takes input from stdin (many commands don't) and that there's only a single input. What about: process-stuff --file <(make-input) \ --extra-data <(make-more-stuff | grep blah) This is the point at which one reaches for tempfiles, usually. The point remains that <() was made for a purpose, yet lacks error handling, thus undermining its usefulness to the point of uselessness. Edit: Isn't substitution using pipes, though? As in FIFO pipes? You get a file descriptor device which is closed at the end of the script. I don't know if the fd is wired directly to the command's stdout or whether the output is written in its entirety to a hidden tempfile first; the former sounds more natural and efficient.

tzahola 9y ago
>I don't know if the fd is wired directly to the command's stdout or whether the output is written in its entirety to a hidden tempfile first; the former sounds more natural and efficient. Nope. <() and >() is equivalent to creating a named pipe with mkfifo and writing to it: tmp_pipe_dir="$(mktemp -d)" mkfifo "$tmp_pipe_dir/pipe" make-input >"$tmp_pipe_dir/pipe" & process-stuff --file "$tmp_pipe_dir/pipe" That's the whole point of it, so that the data can be consumed in parallel with the producer.
- lobster_johnson 9y ago
  Right, that's what I meant. The command is run in a child process with its stdout writing to the pipe. The script gets the read end.
mdaniel 9y ago
Yes, you absolutely have me about the stdin part But, the multiple case example highlights that if (for argument's sake) `make-input` and `make-more-stuff` had run _prior_ to that line, writing their (possibly empty) output to a (file|FIFO), how then would you want bash to behave? It would still open file descriptors to those (file|FIFO)s, which would still be just as blank. It seems to me that if one wishes more fine grained control over the error handling in a multi-subshell-fd-trickery situation, then creating the FIFO(s) and managing the sender's exit status is the supervising script's responsibility. a file descriptor device which is closed at the end of the script I checked, and it's actually not even at the end of the script; those fds only exist for that one child, as `process-stuff` is exec-ed by bash. whether the output is written in its entirety to a hidden tempfile It's not a temp-file, it's an actual file descriptor, which bash `dup2`s for the subprocess, then cheekily uses the `/dev/fd/63` syntax to make appear as a file; you can peer into its brain a little: $ showme() { echo "showme.args=$@" >&2 the_fd="${1##/dev/fd/}" cat <&${the_fd} } $ showme <(date -u) showme.args=/dev/fd/63 Sat Jan 6 21:31:25 UTC 2018 Thanks so much for highlighting this scenario; I learned a ton about how that works researching this answer. That's why I like answering stuff on S.O., too: win-win
- lobster_johnson 9y ago
  Good point about how to abort. Maybe it would be possible to short-circuit the fd somehow, so that the reader got an EOF, and that would in turn cause failure in the program reading the stream. At the same time, any success code from the program should be turned into an error exit code so the script could detect the failure. Not perfect, but arguably better than no failure at all.

tzahola 9y ago

>I don't know if the fd is wired directly to the command's stdout or whether the output is written in its entirety to a hidden tempfile first; the former sounds more natural and efficient. Nope. <() and >() is equivalent to creating a named pipe with mkfifo and writing to it: tmp_pipe_dir="$(mktemp -d)" mkfifo "$tmp_pipe_dir/pipe" make-input >"$tmp_pipe_dir/pipe" & process-stuff --file "$tmp_pipe_dir/pipe" That's the whole point of it, so that the data can be consumed in parallel with the producer.

lobster_johnson 9y ago
Right, that's what I meant. The command is run in a child process with its stdout writing to the pipe. The script gets the read end.

mdaniel 9y ago

Yes, you absolutely have me about the stdin part But, the multiple case example highlights that if (for argument's sake) `make-input` and `make-more-stuff` had run _prior_ to that line, writing their (possibly empty) output to a (file|FIFO), how then would you want bash to behave? It would still open file descriptors to those (file|FIFO)s, which would still be just as blank. It seems to me that if one wishes more fine grained control over the error handling in a multi-subshell-fd-trickery situation, then creating the FIFO(s) and managing the sender's exit status is the supervising script's responsibility. a file descriptor device which is closed at the end of the script I checked, and it's actually not even at the end of the script; those fds only exist for that one child, as `process-stuff` is exec-ed by bash. whether the output is written in its entirety to a hidden tempfile It's not a temp-file, it's an actual file descriptor, which bash `dup2`s for the subprocess, then cheekily uses the `/dev/fd/63` syntax to make appear as a file; you can peer into its brain a little: $ showme() { echo "showme.args=$@" >&2 the_fd="${1##/dev/fd/}" cat <&${the_fd} } $ showme <(date -u) showme.args=/dev/fd/63 Sat Jan 6 21:31:25 UTC 2018 Thanks so much for highlighting this scenario; I learned a ton about how that works researching this answer. That's why I like answering stuff on S.O., too: win-win

lobster_johnson 9y ago
Good point about how to abort. Maybe it would be possible to short-circuit the fd somehow, so that the reader got an EOF, and that would in turn cause failure in the program reading the stream. At the same time, any success code from the program should be turned into an error exit code so the script could detect the failure. Not perfect, but arguably better than no failure at all.