3 ms·
How is 1188 rare? 100 people a month is absurdly common. http://killedbypolice.net/ http://killedbypolice.net/
by dade_ 9y ago
How is 1188 rare? 100 people a month is absurdly common.
http://killedbypolice.net/ http://killedbypolice.net/
- MikeAmelung 9y agoCan't really make that argument without considering the population of a country, right?
- femto 9y agoWikipedia has the numbers: https://en.wikipedia.org/wiki/Police_firearm_use_by_country#Comparison_of_countries https://en.wikipedia.org/wiki/Police_firearm_use_by_country#... Per capita, at least 5 times more people die in the US from police firearms compared to similar countries. Compared to Australia, its about 80x (per capita).
- albntomat0 9y agoOut of a country with a population of 320+ million, with 750,000+ "sworn officers" (able to make arrests) [0], 1188 is not "absurdly common", especially as that count is an overestimate of the objectionable cases (by how much is difficult to determine). The issue with police shooting deaths is not that there is a high likelihood of an individual dieing tomorrow (for reference, drunk driving deaths are 10x police shooting deaths [1]), but the injustice of innocent people being killed. Accurately representing the problem, and avoiding the "all police are terrible" comments is vital to actually trying to fix this, as a solution necessitates actively working with police, the vast majority of which have not, and will never, shoot anyone. [0]: https://www.bjs.gov/content/pub/pdf/nsleed.pdf https://www.bjs.gov/content/pub/pdf/nsleed.pdf [1]: https://www.cdc.gov/motorvehiclesafety/impaired_driving/impaired-drv_factsheet.html https://www.cdc.gov/motorvehiclesafety/impaired_driving/impa...
- OscarCunningham 9y agoIt's a small number of deaths per capita, but quite large per police interaction. So it's possible that the knock-on effects are worse than the injustice. The police would be much less useful if no one ever called them, and why would I call them if there's a significant chance of them killing me or someone else?