Correct! In fact, I already use a poor mans average. Initially newImage is all black and then: b=oldImage[x,y]; xa=(newImage[b,y]+x)/2; // poor mans av

Correct! In fact, I already use a poor mans average. Initially newImage is all black and then: b=oldImage[x,y]; xa=(newImage[b,y]+x)/2; // poor mans average newImage[b,y]=xa; Would a proper average improve the image further? Let's see... ...here we go: No average on the left, poor mans average in the middle, proper average on the right: https://www.productchart.com/elements/objects/blog/2017-12-19-images/averages.jpg https://www.productchart.com/elements/objects/blog/2017-12-1... Yup, it's better. I updated the page with the proper average algorithm now. Thanks, Brian!