> Also, this still doesn't mean there would be a branch on every access, right? Yes it does, without a move constructor the only way to do a small vector optim

> Also, this still doesn't mean there would be a branch on every access, right? Yes it does, without a move constructor the only way to do a small vector optimization is to detect when the vector has been packed in the indexing operation and do the pointer math internal to the stack part of the vector. With move constructors you keep the pointer up to date, without them you have to recalculate this information on any kind of access, and for this you need to know when stuff must be recalculated which leads to the extra branch.