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>Correct! Because in every generation it is far more likely that the mutant strains would be brought "back into the fold" through interbreeding Is that somethi
by macspoofing 9y ago
>Correct! Because in every generation it is far more likely that the mutant strains would be brought "back into the fold" through interbreeding
Is that something you came up with yourself or is it something that mainstream biology acknowledges?
And if random-mutation+selective pressure (i.e. natural selection) is not the primary mechanism for speciation, then what is?
- EGreg 9y agoThat's an argument from authority and argument from ignorance. I am happy to say it's pretty evident we don't know. If we do know, I want to hear the actual substance. What do we know, HOW do we come to know it and where's the proof that mathematically it makes any sense?
- Retric 9y agoMathematically, beneficial mutation X spreads to the population A. Beneficial mutation Y that depends on Y spreads to population A. However without 2 copies of X, Y becomes harmful. So, it only spreads when the population A already has 2 copies of A. Now, population B does not have any copies of X and pairs can only get one copy of X from a parent, but will also get 1 copy of Y from a parent resulting in offspring that have issues. Critically, dependency between mutations is extremely common for example the shape of the bones in your foot are related causing an ever increasing number of incompatible issues. Thus, mathematically independent populations will become less compatible over time. PS: Mules start to show up when only one copy of X is required so getting one X and one Y is enough. However, offspring are not going to always get a copy of X.
- macspoofing 9y ago>That's an argument from authority and argument from ignorance. It's neither. I just asked you where you got your ideas from. And it sounds like you are dismissing an entire field of scholarship because you thought about this really really hard.