Hm; tried to revive some primary school-level physics/chemistry knowledge to calculate price-per-molecule or #-of-molecules-per-£. Is my calculation correct, or

Hm; tried to revive some primary school-level physics/chemistry knowledge to calculate price-per-molecule or #-of-molecules-per-£. Is my calculation correct, or have I botched it? :)  Given atomic mass of C is 12.011, of N is 14.007, the molar mass [1] of the fullerene should be:   M(N@C60) = 14.007 + 60×12.011 [g/mol] = ~734.667 [g/mol]  Then, given:   N_A = 6.022140857e23 [1/mol] — https://en.wikipedia.org/wiki/Avogadro_constant https://en.wikipedia.org/wiki/Avogadro_constant (number of molecules in 1 mol)   p_g = 200e6 [£/g] — price per gram given in article   n = ? [1/£] — number of molecules one would get for £1  I devised:   n = N_A / (p_g × M(N@C60)) = [1/mol] / ([£/g] × [g/mol]) = [1/mol] / [£/mol] = [1/£] = 6.022140857e23 / (200e6 × 734.667) [1/£] = ~ 4e12 [1/£] ? In other words, it seems you could buy ~4'000'000'000'000 molecules for £1 ? — [1] https://en.wikipedia.org/wiki/Molar_mass https://en.wikipedia.org/wiki/Molar_mass