4 ms·
> those are not functions with arguments, they're all 0-arity method calls In other words, they are 1-argument function calls. The "this"/"self" parameter is i
by tom_mellior 9y ago
> those are not functions with arguments, they're all 0-arity method calls
In other words, they are 1-argument function calls. The "this"/"self" parameter is implicit in many languages, but otherwise it's not different from a normal function parameter. In the "method chaining" version of the example, each method call returns a (reference to) a temporary object which is passed as the next method call's "this" parameter.
- bunderbunder 9y agoIn most languages, that's an implementation detail that is hidden by the compiler, and not a part of the semantics of the language itself. More specifically, if the language won't allow me to do both: foo.method(x) and method(foo, x) and have them behave the same way, then I submit that, regardless of what's going on behind the curtain, a n-arity method is not really the same thing as a (n+1)-arity function in that language.
- kd5bjo 9y agoPython is pretty close to this. Assuming that foo is an instance of class Bar, foo.method(x) Is equivalent[1] to Bar.method(foo, x) [1] in the absence of monkey patching on foo