2 ms·
Good point. Think of it as hand-holding your peers instead of hand-holding the compiler. if(x==y) throw "friendly error" // avoids eternal loop ... The compile
by z3t4 9y ago
Good point. Think of it as hand-holding your peers instead of hand-holding the compiler. if(x==y) throw "friendly error" // avoids eternal loop ...
The compiler doesn't care if you get an eternal loop at runtime, and static types wont prevent it.