2 ms·
Apparently void foo() will not error when called with arbitrary values - it's implicitly variadic. This surprised me too, but I confirmed it with gcc, even on -
by FeepingCreature 9y ago
Apparently void foo() will not error when called with arbitrary values - it's implicitly variadic. This surprised me too, but I confirmed it with gcc, even on -std=c1x and with -Wall -Wextra -pedantic.
Learnt something!