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"i" does not store a reference to a type. Values in Haskell aren't tagged with their type like in OOP. There is no "isInstanceOf" check in Haskell.
by bad_user 9y ago
"i" does not store a reference to a type. Values in Haskell aren't tagged with their type like in OOP.
There is no "isInstanceOf" check in Haskell.