3 ms·
No, it's not wavelength change, it's the number of wavelengths that fit in each "arm" of the detector. With 4 km arms and 1000 nanometer laser wavelength (actua
by semi-extrinsic 9y ago
No, it's not wavelength change, it's the number of wavelengths that fit in each "arm" of the detector. With 4 km arms and 1000 nanometer laser wavelength (actual numbers), you will have 4 000 000 000.00 wavelengths that fit in each arm. When a gravitational wave passes, one arm will have 4 000 000 000.10 wavelengths and the other is unchanges. Since we're working with interference, this parts-per-billion change is converted into a large change in light.
Mechanical analogy: there are two very long very fine pitch helical gears that are both suspended from one end and mesh perfectly at the other end. When the gravitational wave makes one gear undetectably longer, we can easily see that the gears no longer mesh.
- komali2 9y agoOh my god they're 4km long, dude this is awesome. Cheers for the analogy and explanation.
- rocqua 9y agoHow do they distinguish between 4 000 000 000.10 and 4 000 000 001.10 wavelengths? Do they simply count how often they cross a full-phase change and keep track of the direction of that change?
- cdelsolar 9y agoInterferometry.