3 ms·
My guess is that using the same disk performs better then round robin ... the disk could for example already have the data in cache, while the other disk has no
by z3t4 9y ago
My guess is that using the same disk performs better then round robin ... the disk could for example already have the data in cache, while the other disk has not. When it comes to optimization - the results are often unexpected. And you would have to do a lot of benchmarks on different disks, loads, use cases etc to make a conclusion, and you might find unexpected outcomes that you did not think about, like both disks being self-bricked at the same time as they have almost the same rw count.
- digikata 9y agoOne could do delayed round-robin. For one day (or other time period), the first-choice disk is disk A, the next time period, disk B... etc. And for intentional non-uniformity, you can vary the time-period.. it's one day for disk A, half a day for B. etc...
- kpil 9y agoWhat is the gain?
- digikata 9y agoPossibly pushing the likelyhood of first failure out, preferably beyond capital lifetime assumptions? Possibly increasing system performance over the lifetime of the SSDs. But, it's possible that this solution is not particularly useful depending on what mixes of equipment and workloads one expects to operate.