3 ms·
temperature, in my simple understanding, is brownian motion. What ever that means in the end, we know that vacuum is a pretty good thermal isolator, so the coun
by posterboy 9y ago
temperature, in my simple understanding, is brownian motion. What ever that means in the end, we know that vacuum is a pretty good thermal isolator, so the counter question should be, why should it cool down? Sure, heat can be given off as radiated photons which is messured coming from the filaments, but you probably don't even begin to understand why, ie. why the T is hot, I sure don't, so the question seems like stabbing in the dark (puns not intended).