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Bitcoin is NOT infinitely divisible. Each Bitcoin is divisible into 10^8. There were reasons to choose this number and isn't arbitrary [1]. [1] https://bitcoin
by sidko 9y ago
Bitcoin is NOT infinitely divisible. Each Bitcoin is divisible into 10^8. There were reasons to choose this number and isn't arbitrary [1].
[1] https://bitcoin.stackexchange.com/questions/31933/why-is-bitcoin-defined-as-having-8-decimal-places https://bitcoin.stackexchange.com/questions/31933/why-is-bit...
- wwwtyro 9y agoIt is arbitrarily divisible. Fitting inside 64 bits is convenient, but hardly an insurmountable engineering challenge. There's libraries that handle this sort of thing with ease.