5 ms·
You're right, you've got me certainly beat by unimaginable orders of magnitude. How does g↑(sub_g)g compare with BB(g)?
by diziet 16y ago
You're right, you've got me certainly beat by unimaginable orders of magnitude.
How does g↑(sub_g)g compare with BB(g)?
- baddox 16y agoI have no idea how they compare. The former is incomprehensible and the latter is both incomprehensible and non-computable. My intuition tells me the latter is much larger, because a computer could "easily" calculate the former.