2 ms·
It does work this way, though. Try the following files: #!/usr/bin/sed -f s/a/b/g s/c/d/g #!/usr/bin/sed -e 's/a/b/g' -f s/c/d/g
by JoachimSchipper 16y ago
It does work this way, though.
Try the following files:
#!/usr/bin/sed -f
s/a/b/g
s/c/d/g
#!/usr/bin/sed -e 's/a/b/g' -f
s/c/d/g
- philh 16y agoIt's not clear to me what point you're trying to make, but the second one gives an error: "-e expression #1, char 2: unknown command: `''", because it's getting a single argument containing a quote. Removing the quotes gives "-e expression #1, char 10: unknown option to `s'", because "s/a/b/g -f" is not a valid sed command. And to illustrate my point about env, sed for me is in /bin. But "#!/usr/bin/env sed -f" doesn't work, because it looks for a program named "sed -f".
- JoachimSchipper 16y agoI was agreeing with you, and providing a simple testcase to show that you were, indeed, right (because I agreed that the behaviour is somewhat surprising). Sorry if that wasn't clear.